Problem 42 Coded triangle numbers

The n^th term of the sequence of triangle numbers is given by, t_n = ½n(n+1); so the first ten triangle numbers are:

1, 3, 6, 10, 15, 21, 28, 36, 45, 55, …

By converting each letter in a word to a number corresponding to its alphabetical position and adding these values we form a word value. For example, the word value for SKY is 19 + 11 + 25 = 55 = t₁₀. If the word value is a triangle number then we shall call the word a triangle word.

Using words.txt (right click and ‘Save Link/Target As…’), a 16K text file containing nearly two-thousand common English words, how many are triangle words?

三角形词的数量

三角形数序列中第 n 项的定义是： t_n = ½n(n+1); 因此前十个三角形数是:

1, 3, 6, 10, 15, 21, 28, 36, 45, 55, …

通过将一个单词中每个字母在字母表中的位置值加起来，我们可以将一个单词转换为一个数。例如，单词SKY的值为19 + 11 + 25 = 55 = t₁₀。如果单词的值是一个三角形数，我们称这个单词为三角形单词。

words.txt (右键另存为)是一个16K的文本文件，包含将近两千个常用英语单词。在这个文件中，一共有多少个三角形词？

file = open('p042_words.txt')

n = [i * (i + 1) / 2 for i in range(1, 100)]

s = ''
for f in file:
    s += f

s = eval(s)


def get_order(c):
    return ord(c) - ord('A') + 1
count = 0
for word in s:
    result = 0
    for c in word:
        result += get_order(c)
    if result in n:
        print word
        count += 1

print count

家里网络太差了，各种github刷不出来……完全没法一天一题啊